Let’s say the problem is (9×108)/(3×105){\displaystyle (9\times 10^{8})/(3\times 10^{5})} Our first step would be to divide the coefficients: 9/3=3{\displaystyle 9/3=3}

To continue our example from above, dividing the bases would look like this: 108/105{\displaystyle 10^{8}/10^{5}} Using the rule of exponents, we’d convert it to 108−105=103{\displaystyle 10^{8}-10^{5}=10^{3}}, because 8−5=3{\displaystyle 8-5=3}

From our example above, the answer would be 3×103{\displaystyle 3\times 10^{3}}

(2×103)/(4×10−8){\displaystyle (2\times 10^{3})/(4\times 10^{-8})} (2/4)×(103/10−8){\displaystyle (2/4)\times (10^{3}/10^{-8})} 0. 5×1011{\displaystyle 0. 5\times 10^{11}} Since the coefficient is less than 1, we now have to convert it to scientific notation: 0. 5=5×10−1{\displaystyle 0. 5=5\times 10^{-1}} Now we multiply the coefficient by the new power of 10 we solved for earlier: (5×10−1)×(1011){\displaystyle (5\times 10^{-1})\times (10^{11})} The solution is 5×1010{\displaystyle 5\times 10^{10}}